(1/2)^n+7=2^4n-2

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Solution for (1/2)^n+7=2^4n-2 equation:



(1/2)^n+7=2^4n-2
We move all terms to the left:
(1/2)^n+7-(2^4n-2)=0
Domain of the equation: 2)^n!=0
n!=0/1
n!=0
n∈R
We add all the numbers together, and all the variables
(+1/2)^n-(2^4n-2)+7=0
We get rid of parentheses
(+1/2)^n-2^4n+2+7=0
We multiply all the terms by the denominator
(+1-2^4n*2)^n+2*2)^n+7*2)^n=0
Wy multiply elements
8n^2+(+1-2^4n*2)^n=0

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